Assignment 2 Solutions
Part of
the homework for 22C:60, Fall 2010
|
a) 10101011110011012 to base 16
ABCD
b) 323300014 to base 16
EF01
c) 215058 to base 16
2345
d) 2650510 to base 16
6789
e) A8CA16 to base 10
43210
Hint: Some patterns should emerge to help you judge your answers.
The problem: Consider the value -123 (a negative decimal number). (1 point)
a) Convert it to a 12-bit signed magnitude binary number.
1000 0111 1011
b) Convert it to a 12-bit one's complement binary number.
1111 1000 0100
c) Convert it to a 12-bit two's complement binary number.
1111 1000 0101
d) Convert it to a 12-bit natural-biased binary number.
0111 1000 0101
e) Convert it to a 4-digit 10's complement decimal number.
9877
H 17767 B "#" B 1 W 32#24QNJFF
Hint: You can use the SMAL assembler to help you with this, but you will need to finish the job of packing the result into 32-bit words by yourself. Also, as in problem 1, when you get it right, the result should be obviously right.
Here is the assembler output:
+000000: 4567 1 H 17767 +000002: 23 2 B "#" +000003: 01 3 B 1 +000004: 89ABCDEF 4 W 32#24QNJFF
The above, packed into a sequence of 32-bit words, is:
000000: 01234567 000004: 89ABCDEF