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Find the following for $f(x) = {x^2 + 3x \over x - 1} = {x(x+3) \over x - 1}$ (if 
they 
exist; if they don't exist, state so).  Use this information to graph $f$.

Note $f'(x) = {(x-3)(x+1) \over (x - 1)^2}$, $f''(x) = {8 \over (x - 1)^3}$

%%Is $f$ even, odd, periodic?  What is the domain and range of $f$?
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[1.5] 1a.) critical numbers: $\underline{-1, 3}$
		

[1.5] 1b.) local maximum(s) occur at $x = \underline{-1}$

[1.5] 1c.) local minimum(s) occur at $x = \underline{-3}$

[1.5] 1d.)  The global maximum of $f$ on the interval [0, 5] is $\underline{none}$ and occurs at $x = 
\underline{none}$

[1.5] 1e.)  The global minimum of $f$ on the interval [0, 5] is $\underline{none}$ and occurs at $x = 
\underline{none}$

[1.5] 1f.) Inflection point(s) occur at $x = \underline{none}$


[1.5] 1g.)  $f$ increasing on the intervals $\underline{(-\infty, -1) \cup (3, \infty)}$

[1.5] 1h.)  $f$ decreasing on the intervals $\underline{(-1, 1) \cup (1, 3)}$

[1.5] 1i.)  $f$ is concave up on the intervals $\underline{(1, \infty)}$

[1.5] 1j.)  $f$ is concave down on the intervals $\underline{(-\infty, 1)}$

[1.5] 1k.)  Equation(s) of vertical asymptote(s): $\underline{x = 1}$

[4] 1l.)  Equation(s) of horizontal and/or 
slant asymptote(s): $\underline{y = x+3}$


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[4.5] 1m.)  Graph $f$
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